1. Find the product –
A. (i) `6\times\frac{2}{3}` (ii) `7\times\frac{1}{5}` (iii) `5\times2\frac{3}{4}` (iv) `3\frac{5}{7}\times28` (v) `2\frac{3}{4}\times5`
B. (i) `\frac{1}{7}\times\frac{1}{9}` (ii) `\frac{1}{45}\times\frac{9}{39}` (iii) `\frac{4}{15}\times\frac{9}{10}` (iv) `\frac{51}{40}\times\frac{64}{34}` (v) `\frac{4}{5}\times\frac{12}{7}`
C. (i) `4\frac{2}{7}\times11\frac{2}{3}` (ii) `9\frac{2}{3}\times4\frac{4}{5}` (iii) `5\frac{5}{6}\times6\frac{3}{7}` (iv) `4\frac{1}{8}\times2\frac{10}{11}` (v) `2\frac{2}{17}\times7\frac{2}{9}\times1\frac{33}{52}`
Solution:
A. (i) `6\times\frac{2}{3}`
`=\frac{12}{3}`
`=4`
(ii) `7\times\frac{1}{5}`
`=\frac{7}{5}`
`=1\frac{2}{5}`
(iii)`5\times2\frac{3}{4}`
`=5\times\frac{11}{4}`
`=\frac{55}{4}`
`=13frac{3}{4}`
(iv) `3\frac{5}{7}\times28`
`=\frac{26}{7}\times28`
`\color{fuchsia} {=26\times4}`
`\color{fuchsia} {=104}`
(v)`2\frac{3}{4}\times5`
`=\frac{11}{4}\times5`
`=\frac{55}{4}`
`=13\frac{3}{4}`
B. (i) `\frac{1}{7}\times\frac{1}{9}`
`=\frac{1}{63}`
(ii) `\frac{1}{45}\times\frac{9}{39}`
`=\frac{1\times1}{5\times39}`
`=\frac{1}{195}`
(iii) `\frac{4}{15}\times\frac{9}{10}`
`=\frac{2\times3}{5\times5}`
`=\frac{6}{25}`
(iv) `\frac{51}{40}\times\frac{64}{34}`
`=\frac{3\times8}{5\times2}`
`=\frac{12}{5}`
`=2\frac{2}{5}`
(v) `\frac{4}{5}\times\frac{12}{7}`
`=\frac{4\times12}{5\times7}`
`=\frac{48}{35}`
C. (i) `4\frac{2}{7}\times11\frac{2}{3}`
`=\frac{30}{7}\times\frac{35}{3}`
`=10\times5`
`=50`
(ii) `9\frac{2}{3}\times4\frac{4}{5}`
`=\frac{29}{3}\times\frac{24}{5}`
`=\frac{29\times8}{5}`
`=\frac{232}{5}`
`=46\frac{2}{5}`
(iii) `5\frac{5}{6}\times6\frac{3}{7}`
`=\frac{35}{6}\times\frac{45}{7}`
`=\frac{5\times15}{2\times1}`
`=\frac{75}{2}`
`=37\frac{1}{2}`
(iv) `4\frac{1}{8}\times2\frac{10}{11}`
`=\frac{33}{8}\times\frac{32}{11}`
`=3\times4`
`=12`
(v) `2\frac{2}{17}\times7\frac{2}{9}\times1\frac{33}{52}`
`=\frac{34}{17}\times\frac{65}{9}\times\frac{85}{52}`
`=25`
2. Evaluate –
(i) `\frac{1}{5}of\frac{1}{7}` (ii)
`\frac{4}{5}of\frac{2}{3}` (iii)`\frac{15}{14}of\frac{7}{5}` (iv) `\frac{3}{22}of2\frac{3}{4}` (v)
`\frac{7}{30}of15`
Solution:
(i) `\frac{1}{5}of\frac{1}{7}`
`=\frac{1}{5}\times\frac{1}{7}`
`=\frac{1}{35}`
(ii) `\frac{4}{5}of\frac{2}{3}`
`=\frac{4}{5}\times\frac{2}{3}`
`=\frac{8}{15}`
(iii) `\frac{15}{14}of\frac{7}{5}`
`=\frac{15}{14}\times\frac{7}{5}`
(iv) `\frac{3}{22}of2\frac{3}{4}`
(v)
`\frac{7}{30}of15`
3. What is
Solution:
=
=
=
4. (i) Evaluating of and (ii) of , determine which one is smaller.
Solution:
(i) of
=
=
(ii) of
=
=
Now, we compare and
and
Since 0.1667 is smaller than 0.3, we can conclude
Thus, of (which simplifies to ) is smaller than of (which simplifies to )
5. Bijit’s has spent part on purchasing copy and pen and parts for geometry instrument box from the amount of money his mother gave him as pocket money and kept the rest in hand. Find the part of money left with Bijit and arrange the three parts in descending order.
Solution:
Given
Part spent on copy and pen =
Part spent on geometry instrument box =
To add these fractions, we need a common denominator. The least common multiple (LCM) of 5 and 7 is 35
Total part spent =
=
=
The part of money left with Bijit, = 1
=
=
So, the part of money left with Bijit is
Now, let's arrange the three parts (money spent on copy and pen, money spent on geometry instrument box, and money left) in descending order,
6. Shyamalee reads hours everyday. Out of it she spends part in studying Mathematics and English, part for in Science and rest in studying other subjects. Find out her different study times and arrange them in ascending order.
Solution:
Given,
The total study time of Shyamalee = hours
= hours
Out of it she spends for Mathematics and English = part
Out of it she spends for Science = part
Out of it she spends for other subjects is
=
=
=
=
=
=
=
Now,
=
=
In ascending order
or <
7. In school competition of ‘Model Reading’ Utpal completed parts of the allotted portion in 3 minutes and Runjun completed parts of the allotted page in the same time. Who read more?
Solution:
Given,
In school competition of ‘Model Reading’ Utpal completed = part
and Runjun completed = part
Convert each fraction to have a denominator of 66
Since
Therefore, Runjun read more.
8. Rita read part of a short story book of 75 pages. How many pages of the book are left to read.
Solution:
Given,
Rita read part of a 75-page book.
The number of pages Rita read =
= 15×3
= 45
Now,
subtract the pages read from the total number of pages
Pages left = 75−45
= 30 pages
So, Rita has 30 pages left to read.
9. A man has ₹ 200 within. He paid one fifth of the amount as bus fare. How much amount was left with him?
Solution:
Given,
The total amount of money the man had = ₹ 200
The bus fare from the total amount =
= 1
= ₹ 40
Therefore, the man has ₹160 left.
10. Each of the two water tanks in Ranjus house, contain 500 litres of water in the morning. parts of water of one tank was used for bathing and washing and parts of water of the other tank was used for cooking. What was the total water remaining in the two tanks?
Solution:
Given,
Ranjus first tank contained water = 500 litres
The amount of water used from the first tank for bathing and washing
=
= 3
= 300 litres
Ranjus second tank contained water = 500 litres
The amount of water used from the second tank for cooking
=
= 1
= 125 litres
Now,
Water remaining in the first tank =500−300
= 200 litres
Water remaining in the second tank=500−125
=375 litres
The total water remaining =200+375
= 575 litres
Therefore, the total water remaining in the two tanks is 575 litres.
11. Bobita took part of a cake for eating. In the mean time her brother came and snatched away from her part. what part of the cake colud Bobita eat ?
Solution:
Given,
Bobita took part of a cake to eat
The amount of cake her brother snatched away from her part
=
=
=
=
Part Bobita could eat =
=
=
=
Therefore, Bobita could eat of the cake.
12. Out of ready made shirt in a shop part are white. part are blue and the rest are yellow. If the number of yellow shirts is 72. What are the numbers shirts of other varities. What is the total number of shirts in shop ?
Solution:
Given,
White shirts = part
Blue shirts = part
Let đĨ be the total number of shirts.
The part of yellow shirts =
=
=
=
=
=
Since the number of yellow shirts is 72
According to Question
Now,
Number of white shirts =
=
= 24
Number of blue shirts =
=
=
= 120
Therefore, the shop has 24 white shirts, 120 blue shirts, and 72 yellow shirts, with a total of 216 shirts.
13. Fill in the blanks
(i) = (ii) (iii) (iv)
Solution:
(i) =
(ii)
(iii)
(iv)
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